Project Euler Problem#21
#python program to sum of all the amicable numbers under 10000
def sum_divisor(num):
list1=[]
for i in range (1,num):
if num%i==0:
list1.append(i)
sum=0
for i in list1:
sum+=i
return sum
sum=0
for i in range(1,10000):
a=sum_divisor(i)
b=sum_divisor(a)
if i==b and a!=i:
sum+=i
print(sum) #31626